Parse error: syntax error, unexpected 'mysqli_query' (T_STRING) in /home/u646264372/public_html/page1.php on line 4 (Opgelost)

<?php
include 'db_config.php';
$commando="INSERT INTO `Persons` ('PersonID','LastName','FirstName') VALUES (NULL,'Jan','Man')";
mysqli_query($commando,);
?>

<?php
include 'db_config.php';
$commando="INSERT INTO `Persons` ('PersonID','LastName','FirstName') VALUES (NULL,'Jan','Man')";
mysqli_query($commando,);
?>

<?php
$sServer = 'localhost';
$sDb_name = 'dbname';
$sUser = 'usernaam';
$sPass = 'password';
mysqli_connect( $sServer, $sUser, $sPass ) or die('Er ging iets mis: ' . mysql_error() );
?>

<?php
$sServer = 'localhost';
$sDb_name = 'dbname';
$sUser = 'usernaam';
$sPass = 'password';
mysqli_connect( $sServer, $sUser, $sPass ) or die('Er ging iets mis: ' . mysql_error() );
?>

$mysqli = new mysqli( "localhost", "username", "password", "dbname" );

$sql = "INSERT INTO `Persons` ('PersonID','LastName','FirstName') VALUES (NULL,'Jan','Man')";

if ( $mysqli->query( $sql ) === TRUE ) {
    echo "Success";
} else {
    echo "Error:" . $mysqli->error;
}

$mysqli->close();

$mysqli = new mysqli( "localhost", "username", "password", "dbname" );
 
$sql = "INSERT INTO `Persons` ('PersonID','LastName','FirstName') VALUES (NULL,'Jan','Man')";
 
if ( $mysqli->query( $sql ) === TRUE ) {
    echo "Success";
} else {
    echo "Error:" . $mysqli->error;
}
 
$mysqli->close();

$sql = "INSERT INTO Persons (LastName,FirstName) VALUES ('Knopfler','Mark')";

$sql = "INSERT INTO Persons (LastName,FirstName) VALUES ('Knopfler','Mark')";