Parse error: syntax error, unexpected T_LOGICAL_OR on line 9 (Opgelost)

<?php

include('../connect.php');

$id = mysql_real_escape_string( $_POST["id"] );

echo "$id <br>";  //zo ben ik zeker dat de $id doorkomt
$sql = mysql_query ("SELECT id, naam,  FROM sponser_beheer WHERE id = '".$id."'");
or die(mysql_error());


?>

<?php
 
include('../connect.php');
 
$id = mysql_real_escape_string( $_POST["id"] );
 
echo "$id <br>";  //zo ben ik zeker dat de $id doorkomt
$sql = mysql_query ("SELECT id, naam,  FROM sponser_beheer WHERE id = '".$id."'");
or die(mysql_error());
 
 
?>

$sql = mysql_query ("SELECT id, naam, FROM sponser_beheer WHERE id = '".$id."'") or die(mysql_error());

$sql = mysql_query ("SELECT id, naam, FROM sponser_beheer WHERE id = '".$id."'") or die(mysql_error());

<?php
if (isset($_POST['id']) && is_numeric($_POST['id'])) {
    $query = 'SELECT id, naam
              FROM sponsor_beheer
              WHERE id = '.mysql_real_escape_string($_POST['id']);

    // je zou $query in je die()-boodschap ook nog kunnen escapen
    $result = mysql_query($query) or die(mysql_error().'<br />'.$query);
}
?>

<?php
if (isset($_POST['id']) && is_numeric($_POST['id'])) {
    $query = 'SELECT id, naam
              FROM sponsor_beheer
              WHERE id = '.mysql_real_escape_string($_POST['id']);
 
    // je zou $query in je die()-boodschap ook nog kunnen escapen
    $result = mysql_query($query) or die(mysql_error().'<br />'.$query);
}
?>