best rated foto's

<?PHP
$sql = mysql_query ("SELECT rating FROM pictures ORDER BY rating DESC LIMIT 3");
?>

<?PHP
$sql = mysql_query ("SELECT rating FROM pictures ORDER BY rating DESC LIMIT 3");
?>

SELECT AVG(ratings.rating) as rate,pictures.naam as fotonaam 
FROM ratings INNER JOIN pictures on rates.fotoID=pictures.ID 
GROUP BY rates.fotoID
ORDER by rate desc limit 3

SELECT AVG(ratings.rating) as rate,pictures.naam as fotonaam 
FROM ratings INNER JOIN pictures on rates.fotoID=pictures.ID 
GROUP BY rates.fotoID
ORDER by rate desc limit 3