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problemen met form

Offline Ronstert - 30/12/2005 22:45 (laatste wijziging 30/12/2005 22:46)
Avatar van RonstertMySQL interesse
php code - Bekijk de code zonder highlighting - Klap code in 
  1. <?
  2.  
  3. if ($submit != "verzenden" || !$naam || !$link) {
  4.  
  5.       $sql = "SELECT * FROM adm_menus WHERE id ='$menuid'";
  6.       $result = mysql_query($sql);
  7.       $menu = mysql_fetch_array($result);
  8.  
  9.       echo "<table width=98% cellpadding=0 cellspacing=0 border=0>";
  10.       echo "<tr><td align=right><img src=layout/headers/optie_toevoegen.gif></td></tr>";
  11.       echo "<tr><td>";
  12.       echo "<form method=\"POST\" name=\"optie_toevoegen\" action=\"?p=menu/optie_toevoegen\">";
  13.       echo "<table width=\"100%\" cellpadding=\"0\" cellspacing=\"0\" bgcolor=\"".$con['table1_color']."\" style=\"".$con['table1_border']."\">";
  14.       echo "<tr>";
  15.       echo "<td width=\"40%\">&nbsp;<img src=../layout/images/arrow.gif> Geselecteerd menu</td><td width=\"2%\">:</td><td><b><input type=\"text\" name=\"menu\" size=\"40\" value=\"".$menu['menu']."\" readonly></b></td>";
  16.       echo "</tr>";
  17.       echo "<tr>";
  18.       echo "<td width=\"40%\">&nbsp;<img src=../layout/images/arrow.gif> Menu naam</td><td width=\"2%\">:</td><td><input type=\"text\" name=\"naam\" size=\"40\" value=\"$naam\">";
  19.             if ($submit && !$naam) {
  20.             echo "<font color=yellow> Invullen!</font>";
  21.             }
  22.       echo "</td>";
  23.       echo "</tr>";
  24.       echo "<tr>";
  25.       echo "<td width=\"40%\">&nbsp;<img src=../layout/images/arrow.gif> Menu link</td><td width=\"2%\">:</td><td><input type=\"text\" name=\"link\" size=\"40\" value=\"$link\">";
  26.             if ($submit && !$link) {
  27.             echo "<font color=yellow> Invullen!</font>";
  28.             }
  29.       echo "</td>";
  30.       echo "</tr>";
  31.       echo "<tr>";
  32.       echo "<td width=\"40%\"></td><td width=\"2%\"></td><td><input type=\"hidden\" name=\"menuid\" size=\"40\" value=\"".$menu['id']."\"></td>";
  33.       echo "</tr>";
  34.       echo "<tr>";
  35.       echo "<td colspan=\"3\" height=\"5\"></td>";
  36.       echo "</tr>";
  37.       echo "<tr>";
  38.       echo "<td colspan=\"2\" align=\"center\"></td><td><input type=\"reset\" name=\"reset\" value=\"Reset\"> <input type=\"submit\" name=\"submit\" value=\"Toevoegen\"></td>";
  39.       echo "</tr>";
  40.       echo "<tr>";
  41.       echo "<td colspan=\"3\" height=\"5\"></td>";
  42.       echo "</tr>";
  43.       echo "</form>";
  44.       echo "</table>";
  45.  
  46.       echo "</td></tr></table>";
  47.  
  48.       } else {
  49.       $sql = "INSERT INTO adm_opties (naam, link, menuid) VALUES (".$_POST['naam'].", ".$_POST['link'].", ".$_POST['menuid'].")";
  50.       $result = mysql_query($sql) or die (mysql_error());
  51.       echo "Succesvol toegevoegd";
  52.       }
  53. ?>


controle gaat allemaal goed.. maar dan moet hij verzenden.... dan gebuert er niks!... ik kan de fout niet vinden, zelfs met mij boekie niet!..

iemand?

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