PHP gevorderde |
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volgens xhtml mag je geen name="" gebruike...
nu heb ik dit script.
<img src="img/layout/affiliate.bmp" name="button" alt="Affiliate" width="88" height="31" />
<?php
//blablabla
echo "<a href=\"javascript:newvenster('".$aaff['url']."')\" onmouseover=\"document.button.src=image".$i.".src\" onmouseout=\"document.button.src=image00.src\">".$aaff['name']."</a><br />\n";
//blablabla
?>
<img src="img/layout/affiliate.bmp" name="button" alt="Affiliate" width="88" height="31" /> <?php //blablabla echo "<a href=\"javascript:newvenster('".$aaff['url']."')\" onmouseover=\"document.button.src=image".$i.".src\" onmouseout=\"document.button.src=image00.src\">".$aaff['name']."</a><br />\n"; //blablabla ?>
en daar moet ik tog egt (lijkt mij) een name=button geve omdat anders niet het plaatje word aangepast. weet iemand een manier waarop dit principe ook werkt en dan xhtml 1.0 strict.
btw dit is wat w3c zegt:
Citaat: Line 248, column 42: there is no attribute "name"
... src="img/layout/affiliate.bmp" name="button" alt="Affiliate" width="88" heig
You have used the attribute named above in your document, but the document type you are using does not support that attribute for this element. This error is often caused by incorrect use of the "Strict" document type with a document that uses frames (e.g. you must use the "Transitional" document type to get the "target" attribute), or by using vendor proprietary extensions such as "marginheight" (this is usually fixed by using CSS to achieve the desired effect instead).
This error may also result if the element itself is not supported in the document type you are using, as an undefined element will have no supported attributes; in this case, see the element-undefined error message for further information.
How to fix: check the spelling and case of the element and attribute, (Remember XHTML is all lower-case) and/or check that they are both allowed in the chosen document type, and/or use CSS instead of this attribute.
niet egt een andwoord waar je wat aan hebt..
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